3^2x+1=4^2x-5

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Solution for 3^2x+1=4^2x-5 equation: 



3^2x+1=4^2x-5

We move all terms to the left:

3^2x+1-(4^2x-5)=0

We get rid of parentheses

3^2x-4^2x+5+1=0

We add all the numbers together, and all the variables

3^2x-4^2x+6=0

We move all terms containing x to the left, all other terms to the right

3^2x-4^2x=-6

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